Pls help me by answering these :(

Answer:
1) 21
2a) -23/30
2b) 6/55
Step-by-step explanation:
1) 3(x + 2) + 5x + 7
expand the brackets:
= 3x + 6 + 5x + 7
collect like terms:
= 8x + 13
when x = 1, (just substitute 1 for x)
8(1) + 13
= 8 + 13
= 21
2a)
-9/10 + 2/15
put both fractions on the same denominator (often we can just multiply each denominator by the other one):
so -9/10 * 15/15
= -135/150
and 2/15 * 10/10
= 20/150
now they're both on the same denominator and we can add the numerators:
-135 + 20 = -115
so our answer is:
-115/150
which we can simplify to:
-23/30
2b)
3/11*2/5
Multiplying fractions is very simple, as it doesn't require to have the same denominators. We can just multiply the numerators by each other and same for the denominators:
3*2 = 6
11*5 = 55
therefore, our answer is:
6/55
A)
3(x+2) + 5x + 7
3x + 6 + 5x + 7
3x + 5x + 6 + 7
put x = 1
3(1) + 5(1) + 6 + 7
3 + 5 + 6 + 7
21
B)
a)
[tex]\sf \rightarrow -\dfrac{9}{10} + \dfrac{2}{15}[/tex]
[tex]\sf \rightarrow -\dfrac{9(15)}{150} + \dfrac{2(10)}{150}[/tex]
[tex]\sf \rightarrow -\dfrac{135}{150} + \dfrac{20}{150}[/tex]
[tex]\sf \rightarrow \dfrac{-135+20}{150}[/tex]
[tex]\sf \rightarrow \dfrac{-115}{150}[/tex]
[tex]\sf \rightarrow \dfrac{-23}{30}[/tex]
b)
[tex]\sf \rightarrow \dfrac{3}{11} \ * \ \dfrac{2}{5}[/tex]
[tex]\sf \rightarrow \dfrac{3*2}{11 *5}[/tex]
[tex]\sf \rightarrow \dfrac{6}{55}[/tex]