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A bullet is fired straight up with a muzzle velocity of 1200 ft/s. How high does the bullet go, neglecting any air resistance?

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asuwafohjames

The height of the bullet as it travels is 72727.27 ft.

What is height?

Height is the vertical distance between two points. The unit of height is meter (m).

To calculate the height the bullet will go, we use the formula below

Formula:

  • v² = u²+2gH.............. Equation 1

Where:

  • v = Final velocity of the bullet
  • u = initial velocity of the bullet
  • g = acceleration due to gravity
  • H = Height the bullet will go.

Make H the subject of the equation

  • H = (v²-u²)/2g................ Equation 2

From the question,

Given:

  • u = 1200 ft/s
  • v = 0 m/s (at maximum height)
  • g = -9.8 m/s² (against gravitational force)

Substitute these values into equation 2

  • H = (0²-1200²)/2×(-9.8)
  • H = -1440000/-19.8
  • H = 72727.27 ft.

Hence, The height of the bullet as it travels is 72727.27 ft.

Learn more about height here: https://brainly.com/question/1739912

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