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A boat heading out to sea starts out at point aa, at a horizontal distance of 770 feet from a lighthouse/the shore. From that point, the boat’s crew measures the angle of elevation to the lighthouse’s beacon-light from that point to be 14^{\circ} ∘. At some later time, the crew measures the angle of elevation from point bb to be 8^{\circ} ∘. Find the distance from point aa to point bb. Round your answer to the nearest tenth of a foot if necessary

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ogorwyne

With the angle of elevation at 8 degrees and 14, the distance from point A to point B would be 596.72 feet.

How to solve for the distance in feet

tan < CAD = CD/AC

we have to cross multiply here so that

CD = AC * tan < CAD

AC = 770

tan < CAD = tan 14 degrees

tan < B = CD/BC

BC = CD/tab<B

= 770*tan 14/tan8

= 770*0.2493/0.1405

= 1366.72 feet

AB =  BC - AC

= 1366.72 - 770

= 596.72 feet

We can conclude that the distance that exists from point a to b is 596.72 feet.

Read more on distance here: https://brainly.com/question/2854969

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