The standard form of the given equation [tex]x^2+y^2-18x+8y+5=0[/tex] will be given as [tex](x-9^2)+(y+4)^2=(2\sqrt{23} )^2[/tex]
What is the equation of a circle?
The general form of the equation of the circle is given as
[tex](x-h)^2+(y-k)^2=r^2[/tex]
We have the equation
[tex]x^2+y^2-18x+8y+5=0[/tex]
By adding 81 and 16 on both sides
[tex]x^2-18x+81+y^2+8y+16=-5+81+16[/tex]
[tex](x-9)^2+(y+4)^2=92[/tex]
[tex](x-9)^2+(y+4)^2=(2\sqrt{23})^2[/tex]
Thus the standard form of the given equation [tex]x^2+y^2-18x+8y+5=0[/tex] will be given as [tex](x-9^2)+(y+4)^2=(2\sqrt{23} )^2[/tex]
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