The expression which is equal to the given complex fraction will be
(2-(1/y)/3+(1/y)=(2y-1)/(3y+1)
The complex fraction will be defined as the expression containing the fractions in their numerator and denominator or at least one of them like either numerator or denominator containing fraction in it.
now we have to find the solution to the given expression:
[tex]=\dfrac{2-\frac{1}{y} }{3+\frac{1}{y} }[/tex]
[tex]=\dfrac{\dfrac{2y-1}{y} }{\dfrac{3y+1}{y} }[/tex]
[tex]=\dfrac{2y-1}{3y+1}[/tex]
Hence the expression which is equal to the given complex fraction will be
[tex]\dfrac{2-\frac{1}{y} }{3+\frac{1}{y} }= \dfrac{2y-1}{3y+1}[/tex]
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