The volume of the cone is 35069.35ft^3 which is equivalent to the air the heating and cooling system would accommodate
Data;
The shape of a cone has a spherical base. From the given data, we can find radius of the sphere from this.
[tex]A = \frac{4}{3}\pi r^3\\38000 = \frac{4}{3}* 3.14 * r^3\\4.186r^3 = 38000\\r^3 = \frac{38000}{4.186} \\r^3 = 9077.878\\r = \sqrt[3]{9077.878} \\r = 20.86ft[/tex]
The volume of a cone is given as
[tex]v=\frac{1}{3} \pi r^2 h\\v = \frac{1}{3} * 3.14 * 20.86^2 * 77\\v = 35069.35ft^3[/tex]
The volume of the cone is 35069.35ft^3
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