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A regulation 145 g baseball can be hit at speeds of 100 mph. If a line drive is hit essentially horizontally at this speed and is caught by a 65 kg player who has leapt directly upward into the air, what
horizontal speed does he acquire by catching the ball?

Respuesta :

hamzaahmeds

This question involves the concept of the law of conservation of momentum.

The horizontal speed acquired by catching the ball will be "0.223 mph".

Law of Conservation of Momentum

According to the law of conservation of momentum applied in horizontal direction:

Total Initial Momentum = Total Final Momentum

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

  • m₁ = mass of baseball = 145 g = 0.145 kg
  • m₂ = mass of player = 65 kg
  • u₁ = initial horizontal speed of baseball = 100 mph
  • u₂ = initial horizontal speed of player = 0 mph
  • v₁ = final horizontal speed of baseball = 0 mph
  • v₂ = final horizontal speed of player = ?

Therefore,

[tex](0.145\ kg)(100\ mph)+(65\ kg)(0\ mph)=(0.145\ kg)(0\ mph)+(65\ kg)(v_2)\\\\v_2=\frac{14.5\ kg.mph}{65\ kg}\\\\[/tex]

v₂ = 0.223 mph

Learn more about the law of conservation of momentum here:

https://brainly.com/question/1113396

RayEto

This is less an answer more like the answers that should be it.

A) 9.9 cm/s

B) 5.6 cm/s

C) 11.8 cm/s

D) 4.2 cm/s

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