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Answer:

An airplane is flying at an airspeed of 200 miles per hour headed on a SE bearing of 140°. A north wind (from north to south) is blowing at 16.2 miles per hour, as shown in Figure 8.8.1. What are the ground speed and actual bearing of the plane?

Explanation:

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θ = 205° - 105° = 100°

[tex]\tt R=\sqrt{L^2+M^2+2LMcos\theta}\\\\R=\sqrt{303^2+555^2+2.303.555cos100}\\\\R=584.32~m[/tex]