Answer:
4m^2-12m+9
Step-by-step explanation:
[tex](2m -3)^2[/tex]
[tex]\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2[/tex]
[tex]\left(2m-3\right)^2=\left(2m\right)^2-2\cdot \:2m\cdot \:3+3^2[/tex]
[tex]=\left(2m\right)^2-2\cdot \:2m\cdot \:3+3^2[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]=4m^2-12m+9[/tex]
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Answer:
[tex] \bf \longrightarrow \: ( {2m - 3)}^{2} [/tex]
Using Identity
Let,
a = 2m
b = 3
Now
[tex] \sf \longrightarrow \:(2m) {}^{2} + {3}^{2} - 2(2m \times 3) \\ \\ \\ \sf \longrightarrow \:4 {m}^{2} + 9 \: - 2(6m) \\ \\ \\ \sf \longrightarrow \:4 {m}^{2} + 9 \: - 12m[/tex]
Therefore,
