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two freight cars each with a mass of 3.0 * 10^5 kg collide and stick together. One was initially moving at 2.2 m/s, and the other was at rest. What is their final speed? Define the system as the two cars.​

Respuesta :

Answer:

1.1 m/s

Explanation:

We know in an inelastic collision, applying the principle of conservation of momentum :-

  • m₁v₁ + m₂v₂ = (m₁ + m₂)v
  1. m₁ = mass of object 1 = 3 x 10⁵ kg
  2. m₂ = mass of object 2 = 3 x 10⁵ kg
  3. v₁ = initial speed of object 1 = 2.2 m/s
  4. v₂ = initial speed of object 2 = 0 m/s (rest)
  5. v = final combined speed = ?

Substituting the values

  • 3 x 10⁵(2.2) + 3 x 10⁵(0) = (3 x 10⁵ + 3 x 10⁵)v
  • 6.6 x 10⁵ = 6 x 10⁵ x v
  • v = 6.6/6
  • v = 1.1 m/s

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