Respuesta :
Using the normal probability distribution and the central limit theorem, it is found that the probability is of 0.9974 = 99.74%, which means that the pilot should take action.
Normal Probability Distribution
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
In this problem, for the population, the mean and the standard deviation are given by, respectively:
[tex]\mu = 185.47, \sigma = 39[/tex].
For a sample of 37 passengers, we have that:
[tex]n = 37, s = \frac{39}{\sqrt{37}} = 6.4116[/tex]
The probability that the aircraft is overloaded is one subtracted by the p-value of Z when X = 167.6, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem:
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{167.6 - 185.47}{6.4116}[/tex]
[tex]Z = -2.79[/tex]
[tex]Z = -2.79[/tex] has a p-value of 0.0026.
1 - 0.0026 = 0.9974.
There is a 0.9974 = 99.74% probability that the aircraft is overloaded. Since this is a very high probability, the pilot should take action.
To lern more about the normal probability distribution and the central limit theorem, you can check https://brainly.com/question/24663213
