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If a beach ball has a volume of 261 L at a temperature of 502 K, what will be the new
temperature of the balloon if the volume decreases to 176 L? Formula: V/T, -V2/T2

Respuesta :

nuhulawal20

The new temperature of the balloon if the volume is decreased to the given amount is 338.5K.

Charles's law

Charles's law states  that the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

Given the data in the question;

  • Initial volume; [tex]V_1 = 261L[/tex]
  • Initial temperature; [tex]T_1 = 502K[/tex]
  • Final volume; [tex]V_2 = 176L[/tex]

Final Temperature; [tex]T_2 = \ ?[/tex]

To determine the new temperature as the volume is decrease, we substitute our given values into the expression above.

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}\\\\V_1T_2 = V_2T_1\\\\261L * T_2 = 176L * 502K\\\\261L * T_2 = 88352L.K\\\\T_2 = \frac{88352L.K}{261L}\\ \\T_2 = 338.5K[/tex]

Therefore, the new temperature of the balloon if the volume is decreased to the given amount is 338.5K.

Learn more about Charles's law: https://brainly.com/question/12835309

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