Answer:
The volume occupied by the air inside the hot balloon is 2.67 L.
Explanation:
Initial volume of the balloon =[tex]V_1= 2.50 L[/tex]
Initial temperature of the air inside the balloon [tex]T_1= 22.0 °C = 295 K[/tex]
Final volume of the balloon = [tex]V_2[/tex]
Final temperature of the air inside the balloon =[tex]T_2= 43.0 °C = 316 K[/tex]
Using Charles law:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
[tex]V_2=\frac{V_1\times T_2}{T_1}=\frac{2.50 L\times 316 K}{295 K}=2.67 L[/tex]
The volume occupied by the air inside the hot balloon is 2.67 L.
