Answer:
C
Explanation:
The reaction between carbon dioxide and lithium hydroxide can be represented by the equation:
[tex]\displaystyle \text{CO$_2$} + 2\text{LiOH} \longrightarrow \text{Li$_2$CO$_3$}+ \text{H$_2$O}[/tex]
We want to determine the amount of moles of LiOH needed to react completely with 25.5 g of CO₂.
Determine the number of moles of CO₂ in 25.5 g of CO₂:
[tex]\displaystyle 25.5\text{ g CO$_2$} \cdot \frac{1\text{ mol CO$_2$}}{44.01\text{ g CO$_2$}} = 0.579\text{ mol CO$_2$}[/tex]
Use stoichiometry to determine the amount of LiOH necessary. CO₂ and LiOH are in a 1:2 ratio. That is, for every one mole of CO₂ that reacts, two moles of LiOH must also react.
[tex]\displaystyle 0.579\text{ mol CO$_2$} \cdot \frac{2\text{ mol LiOH}}{1\text{ mol CO$_2$}} = 1.16\text{ mol LiOH}[/tex]
In conclusion, our answer is C.
