Can someone help me solve these pls?


Answer:
Question 1. [tex]y=5[/tex]
Question 2. [tex]y=4[/tex]
Step-by-step explanation:
1. [tex]y^{3} =125[/tex]
Take the cube root of both sides:
[tex]{y}=\sqrt[3]{125} \\[/tex]
or
[tex]y=125^{\frac{1}{3} }[/tex]
[tex]y=5[/tex]
2. [tex]y^{2}+4=20\\[/tex]
Subtract 4 from both sides.
Then you have:
[tex]y^{2} =16[/tex]
Take the square root of both sides:
[tex]y=\sqrt{16}[/tex]
[tex]y=4[/tex]