contestada

what is an equation of a line that is parallel to y=3x-8 and passes through the point (4,-5)

Respuesta :

slope = 3
passing (4,-5)
y = mx + b
-5 = 3(4) + b
-5 = 12 +b 
b = -17

equation
y = 3x - 17
equestriangirl131
Any line that is parallel to another line will have the same slope. To find the equation us the formula:
[tex](y - y_{1}) = m(x - x_{1})[/tex]
m = 3
[tex] x_{1} = 4 y_{1} = -5[/tex]
( y - -(5)) = 3(x - 4)
y + 5 = 3x - 12
y = 3x - 17
The equation for a line parallel to 3x - 8 and passes through the point (4, -5) is y = 3x - 17.

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