The probability of rolling a 1 or a 2 is P = 4/9, this means that around 4/9 out of the N times we perform the experiment, we will see a 1 or a 2.
We assume that each number has the same probability of rolling up in both dices.
So, in each dice, the probability of rolling a 1 or a 2 is 2 out of 6, or:
p = 2/6 = 1/3
And if we get these on one of the dice, we don't want them in the other,
The probability of not rolling a 1 or a 2 is:
q = 4/6 = 2/3
The joint probability is the product of the two individual probabilities:
P = (1/3)*(2/3)
But, we also need to consider the case where we don't get an 1 or a 2 in the first dice roll, and we do get it on the second dice, then there are 2 permutations, so we need to add a factor 2.
P = 2*(1/3)*(2/3) = 4/9
Now we want to find how often a 1 or a 2 appear against the total number of appearances.
If the total number of appearances is N, then in 4/9 of these, the number 1 or 2 will appear, this is:
N*(4/9) times.
If you want to learn more about probability, you can read:
https://brainly.com/question/251701
