LAY
STOP
Solve using the Zero Product Property.
15. The height of a football after it has been kicked from the top of a hill can be modeled
by the equation h= 2(-2-4t) (2t - 5), where h is the height of the football in feet
and tiltihe time in seconds. How long is the football in the air?
A
A. t=2.5 seconds
B.
B. t=-0.5 seconds
с
C. t=1.5 seconds

Respuesta :

Answer:

A

Step-by-step explanation:

how long is the ball in the air ?

that is the same as asking : after how many seconds will the ball hit the ground (= reach the height of 0) ?

so, that means we need to find the zero solution of h(t).

at what t is h(t) = 0 ?

when at least one of the factors is 0 :

2(-2 - 4t)(2t - 5)

we have 3 factors

2 : can never be 0.

(-2 -4t) : can only be 0 for negative t, which does not make sense in our scenario (we cannot go back in time, only forward).

(2t - 5) : is 0 when 2t = 5 or t = 2.5

so, A is the right answer.

FYI : the starting height (on the hill) is given by t = 0 :

2(-2 - 0)(0 - 5) = 2×-2×-5 = 20 ft