Respuesta :

The equation [tex]f(t) = \sin(2t)[/tex] is an illustration of a sine function

  • The amplitude of the function is 1
  • The period of the function is [tex]\pi[/tex]

How to determine the amplitude?

The equation of the sine function is given as:

[tex]f(t) = \sin(2t)[/tex]

A sine function is represented as:

[tex]f(t) = A\sin(B(t + C)) + D[/tex]

Where

A represents the amplitude

By comparison;

A = 1

Hence, the amplitude of the function is 1

How to determine the period?

In (a), we have:

[tex]f(t) = A\sin(B(t + C)) + D[/tex]

Where the period is:

[tex]T = \frac {2\pi}B[/tex]

By comparison;

B = 2

So, we have:

[tex]T = \frac {2\pi}2[/tex]

[tex]T = \pi[/tex]

Hence, the period of the function is [tex]\pi[/tex]

Read more about sine wave functions at:

https://brainly.com/question/23214084