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A block-spring system oscillates on a frictionless horizontal surface. The time needed for the block to complete one cycle is 0.1 sec. Determine the time needed for the block to travel from -A/2 to A/2, where A is the amplitude of motion.​

Respuesta :

The time required for the block to travel or complete it's half-cycle is 0.05s

Data;

  • time = 0.1s
  • distance = -A/2 to A/2

Amplitude of a Simple Harmonic Motion

This is the maximum displacement of a body from it's mean position.

Assuming a system start from its mean position i.e mean initial position and go to A/2 towards right and then back to his mean position after going through -A/2 then it is said to have completed one cycle. If the block oscillate only between -A/2 to A/2 then it will complete half cycle then it's time period will be 0.05 sec.

Learn more on amplitude here;

https://brainly.com/question/21124447

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