Answer:
[tex]k=3[/tex]
Step-by-step explanation:
Given the following question:
[tex]\frac{9-2k}{3} =k-2[/tex]
To find the answer we need to isolate k, in order to do that we need to use inverse of operations to cancel out integers on each side of the expression.
[tex]\frac{9-2k}{3} =k-2[/tex]
[tex]3\times0=0[/tex]
[tex]2\times3=6[/tex]
[tex]9-2k=k\times3-6[/tex]
[tex]9-9=0[/tex]
[tex]-6-9=15[/tex]
[tex]k\times3=3k[/tex]
[tex]-2k=3k-15[/tex]
[tex]-2k-2k=0[/tex]
[tex]3k+-3k=-5k[/tex]
[tex]-5k=-15[/tex]
[tex]-5k\div-5=k[/tex]
[tex]-15\div-5=3[/tex]
[tex]k=3[/tex]
Your answer is "k =3."
Hope this helps.
