Answer:
[tex]0.71\pi\: in^2[/tex]
Step-by-step explanation:
[tex]r_1= 3.5\: in[/tex]
[tex]r_2= 3.6\: in[/tex]
[tex]A_1=\pi r_1^2=\pi(3.5)^2= 12.25\pi \:in^2[/tex]
[tex]A_2=\pi r_2^2=\pi(3.6)^2= 12.96\pi \:in^2[/tex]
[tex]Difference\: in \:area =A_2-A_1=0.71\pi\:in^2[/tex]
[tex]\implies Error \:in\: the \:area \:of\: the \:circle = 0.71\pi\: in^2[/tex]