Answer:
No biscuits.
Step-by-step explanation:
We know that there is a total of 100 biscuits.
Let's assign variables.
X=Icing
Y=Hundreds and Thousands
Z=Cherries
X appears every 5 biscuits, y appears every 8 biscuits, and z appears every 9 biscuits. Let's start solving by finding their multiples that are less than or equal to 100.
X: 5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100
Y: 8,16,24,32,40,48,56,64,72,80,88,96
Z: 9,18,27,36,45,54,63,72,81,90,99
The multiples need to be a multiple of 5,8, and 9.
The numbers that have both x and y are: 40 and 80
The numbers that have both x and z are: 45 and 90.
Seeing as the numbers never overlap, there are no biscuits that have x,y, and z.
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