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1. The first three terms and the last term of a finite arithmetic sequence are - 92,- 88. -
84, ...,12.Find the number of terms in the sequence.
A. 20
B. 25
C. 27
D. 30

Respuesta :

ianaiman0212pf3cto
Common difference = -88 - (-92)
= 4
First term = -92
Formula -> Tn = First term + (n-1)d

12 = -92 + (n-1)(4)
104 = 4n-4
108= 4n
n= 27

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