The length of a rectangle is 5m longer than the width. The perimeter of the rectangle is 82m. Find the length and width of the rectangle.

Let w represent the width in meters. Then (w+5) represents the length. These values can be put into the perimeter formula, which can be solved to find w.

P = 2(L +W)

82 = 2((w+5) +w) . . . . fill in for L and W

41 = 2w +5 . . . . . . . . divide by 2

36 = 2w . . . . . . . . . subtract 5

18 = w . . . . . . . . . divide by 2. This is the width.

w+5 = 18+5 = 23 . . . . find the length

The length of the rectangle is 23 m; the width is 18 m.

The length of a rectangle is 5m longer than the width. The perimeter of the rectangle is 82m. Find the length and width of the rectangle.​

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The length of a rectangle is 5m longer than the width. The perimeter of the rectangle is 82m. Find the length and width of the rectangle.