Respuesta :
dso in year 6
for x=6
p(6)=6³+6²-2(6)+27
p(6)=216+36-12+27
p(6)=252+15
p(6)=267
in hundreds of dollars
time 100
267 times 100=26700
D is answer
for x=6
p(6)=6³+6²-2(6)+27
p(6)=216+36-12+27
p(6)=252+15
p(6)=267
in hundreds of dollars
time 100
267 times 100=26700
D is answer
Answer:
Option D is correct
the yearly profit in year 6 is, $26,700
Step-by-step explanation:
As per the statement:
The yearly profits of a new small business, in hundreds of dollars, during its first 10 years can be modeled as:
[tex]p(x) =x^3+x^2-2x+27[/tex] ....[1]
where, x is the number of years.
We have to find the yearly profit in 6 years.
⇒[tex]x = 6[/tex]
Substitute in [1] we have;
[tex]p(6) =6^3+6^2-2(6)+27[/tex]
⇒[tex]p(6)=216+36-12+27[/tex]
⇒[tex]p(6) = 267[/tex]
Since, p(x) represents the yearly profit in hundreds of dollars.
[tex]p(6) = \$26, 700[/tex]
therefore, the yearly profit in year 6 is, $26,700