Respuesta :
the board must be at least as big as the project's length needed,
so, it needs to be at least [tex]\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right) \\ \quad \\ or \\ \quad \\ 5\cdot \left( 2\frac{3}{4} \right)\implies \boxed{?}[/tex]
so, it needs to be at least [tex]\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right)+\left( 2\frac{3}{4} \right) \\ \quad \\ or \\ \quad \\ 5\cdot \left( 2\frac{3}{4} \right)\implies \boxed{?}[/tex]
Answer:
The length of the board is 13.75 ft.
Step-by-step explanation:
Given : Philly and Boston were working on a project in carpentry class. They needed to cut 5 lengths of [tex]2\frac{3}{4}[/tex] feet from a board.
To find : How long must the board be to allow this?
Solution :
They needed to cut 5 lengths of [tex]2\frac{3}{4}[/tex] feet from a board.
Let x be the length of the board which is cut into 5 parts and those part length is [tex]2\frac{3}{4}[/tex]
So, The board must be at least as big as the project's length needed,
i.e, [tex]x=5 \times2\frac{3}{4}[/tex]
Now, we solve the expression,
[tex]x=5 \times\frac{11}{4}[/tex]
[tex]x=\frac{55}{4}[/tex]
[tex]x=13.75 ft.[/tex]
Therefore, The length of the board is 13.75 ft.
