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A painter places an 11-ft ladder against a house. The base of the ladder is 3 ft from the house. How high on the house does the ladder reach?

Respuesta :

use Pythagoras theorem
 11^2 = h^2 + 3^2  where h is the height of ladder agaianst the wall

h^2 = 11^2 - 3^2
       =(11+3)(11-3) = 14 * 8 =  112
h = sqrt 112 =  10.58 ft

Answer:

The ladder reach 10.58 feet

Step-by-step explanation:

In this problem a rectangle triangle is formed, with hypotenuse = 11 feet, a side = 3 feet and the other side is the unknown, i. e., how high on the house the ladder reach.  

From Pythagorean theorem:

hypotenuse^2 = side^2 + side^2

11^2 = 3^2 + side^2

side^2 = 11^2 - 3^2

side = sqrt(112)

side = 10.58 feet

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