Find the missing length pleaseeee!!!

Step-by-step explanation:
9.
[tex] \frac{15}{x} = \frac{10}{32} \\ x = 48[/tex]
So QR = 48
10.
[tex]since \: \: \frac{9}{13.5} = \frac{12}{18} \: \: we \: have \\ \\ \frac{12}{18} = \frac{10}{x} \\ x = 15[/tex]
So QP is 15