Answer:
Your answer is 209 J.
Explanation:
First find △T by subtraction of two temperatures.
△T = 18°C - 13 °C
= 5°C.
Q=mc△t
where,
m= mass.
c = Specific Heat .
t = temperature.
As, Specific Heat capacity of water is 4.18 J/g°C
= 10 × 4.18× 5
= 209 Joules.
When a 10g sample of liquid water increases in temperature from 13°C to 18°C, then the amount of gained energy is 209 joules.
The amount of energy which is gained by any sample will be calculated as:
Q = mcΔT, where
Q = gained energy
m = mass of sample = 10g
c = specific heat of water = 4.18 J/g°C
ΔT = change in temperature = 18 - 13 = 5°C
On putting values we get
Q = (10)(4.18)(5)
Q = 209 Joules
Hence required amount of energy is 209 joules.
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https://brainly.com/question/21704399
