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An ideal gas, initially at a volume of 6 L and pressure of 8 kPa, undergoes isothermal expansion until its volume is 8 L and its pressure is 6 kPa. Calculate the work done by the gas during this process. Answer in units of J.

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onyebuchinnaji

The work done by the gas against an external pressure during the isotherma expansion is -12 J.

Work done by the gas against an external pressure

The work done by the gas against an external pressure during the isotherma expansion is calculated as follows;

W(net) = ΔP x ΔV

where;

  • ΔP is the change in pressure for the cyclic process
  • ΔV is change in volume

W(net) = (6 kPa - 8kPa) x (8L - 2L)

W(net) = - 12 kPa.L

W(net) = -12 J

Thus, the work done by the gas against an external pressure during the isotherma expansion is -12 J.

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