The maximum pH an aqueous solution of 0.050 M Cu(NO3)2 is mathematically given as
pH=5.8
What is the maximum pH an aqueous solution of 0.050 M Cu(NO3)2 can be adjusted to before a precipitate of Cu(OH)2 will form?
Generally, the equation for the Chemical reaction is mathematically given as
Cu(OH)2----><---Cu^2 +2OH-
Therefore
s^2=1.0*10^{-19}
s=3.16*10^{=9}
{OH-}=2s=6.3*10^10^{-19}
{H+}=10^{-14}/OH
{H+}=1.58*10^{-6}
In conclusion
pH=-log(1.58*10^{-6}
pH=5.8
Read more about Chemical reaction
https://brainly.com/question/16416932
