Q1: Solutions: x = 2 and x = 4, Axis of symmetry: x = 3.
Q3: (x, y) = (-3, 5).
Q4: A parabola cannot have both a minimum and maximum point because it is only bounded by its vertex.
Q5: [tex]x \in \mathbb{R}[/tex]
Q6: [tex]y \in [-5, + \infty)[/tex]
How to analyze second order polynomials graphically
Graphically speaking, second order polynomials are represented by parabolas. In this question we must interpret the graphs to find all the required information.
Question 1
The solutions to the graph are those values of x such that the graph goes through the x-axis and the axis of symmetry is a line that goes through the vertex ot the parabola and is perpendicular to the width of the curve.
Thus, the solutions to the graph are x = 2 and x = 4 and the axis of symmetry is x = 3. [tex]\blacksquare[/tex]
Question 3
The vertex is the extreme point of a parabola, which may be a minimum or a maximum, but never both. The vertex of the parabola is located at (x, y) = (-3, 5). [tex]\blacksquare[/tex]
Question 4
A parabola cannot have both a minimum and maximum point because it is only bounded by its vertex. [tex]\blacksquare[/tex]
Question 5
The domain of the function is defined by the set of x-values such that the function exists. Thus, the domain of the quadratic function is [tex]x \in \mathbb{R}[/tex]. [tex]\blacksquare[/tex]
Question 6
The range of the function is defined by the set of y-values such that the function exists. Thus, the range of the quadratic function is [tex]y \in [-5, + \infty)[/tex]. [tex]\blacksquare[/tex]
To learn more on parabolas, we kindly invite to check this verified question: https://brainly.com/question/4074088
