The probability that Jamie will be selected as the third player, given that Taylor is selected as one of the is 22%.
Probability
Let J represent the event that junior is selected
Let S represent the event that senior is selected
Hence:
Probability when Jamie is selected as the last person
P(JSJ) or P(SJJ)
P(JSJ) =6/14×8/13×5/12
P(JSJ) =10/91
P(SJJ) =8/14×6/13×5/12
P(SJJ) =10/91
P(Jamie selected)=P(JSJ) + P(SJJ)
P(Jamie selected)=10/91+10/91
P(Jamie selected)=20/91
P(Jamie selected)=0.2198×100
P(Jamie selected)=21.98%
P(Jamie selected)=22% (Approximately)
Therefore the probability that Jamie will be selected as the third player, given that Taylor is selected as one of the is 22%.
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