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A 22 ohm resistor and a 33 ohm resistor are connected in series and placed across a 120-v potential differance

a. What is the equivalent resistance of the circuit?

b. What is the current in the circuit?

c what is the voltage drop across each resistor?

d what is the voltage drop across the two resistors together?

Respuesta :

jcherry99

Answer:

Explanation:

Part A

Resistances in Series Add

Rt = R1 + R2

Rt = 33 + 22

Rt = 55 ohms

Part B

Current is found by using ohms law

I = E/R

E = 120 volts

R = 55 ohms

I = 120/55

I = 2.18

Part C

a)

E = I * R

E = ?

I = 2.18

R = 22 ohms

E = I * R

E = 2.18 * 22

E = 48 volts when I is not rounded in Part B

b)

E = I * R

E = ?

I = 2.1818...

R = 33

E = 2.181818... * 33

E = 72 when the repeating decimal is allowed to repeat.

Part D

The total voltage drop across both resistors adds

E = 72 + 48

E = 120 Volts

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