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Suppose that there are two types of tickets to a show advance and same day the combined cost of one advance ticket and one same-day ticket is $70 for one performance 20 advance tickets and 35 same day tickets were sold.The total amount paid for the tickets was $1850.what was the price of each kind of ticket

Respuesta :

The price of the advance ticket is  $40 and the price of the same day tickets is $30.

What are the linear equations that reperesent the question?

a + b = $70 equation 1

20a + 35b = 1850 equation 2

Where:

a = cost of one advance ticket

b = cost of one same day ticket

What is the cost of one same day ticket?

Multiply equation 1 by 20

20a + 20b = 1400 equation 3

Subtract equation 3 from equation 2

15b = 450

Divide both sides by 15

b = $30

What is the cost advance ticket?

Subtract $30 from $70.

$70 - $30 = $40

To learn more about simultaneous equations, please check: https://brainly.com/question/25875552

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