Respuesta :
Answer:
- [tex]\boxed{\sf{r=-\dfrac{2}{3} }}[/tex]
Step-by-step explanation:
Isolate the term of r, from one side of the equation.
3/2r=-1
First, multiply by 2 from both sides.
2*3/2r=2(-1)
Solve.
3r=-2
Then, you divide by 3 from both sides.
3r/3=-2/3
Solve.
Divide the numbers from left to right.
r=-2/3
-2/3=-0.66
[tex]\Longrightarrow: \boxed{\sf{r=-\dfrac{2}{3}}}[/tex]
- Therefore, the correct answer is r=-2/3.
I hope this helps! Let me know if you have any questions.
Answer:
[tex]{ \qquad{ {{ \tt{ - \frac{2}{3} }}}}} \\ \\[/tex]
Given equation,
[tex] \\ { \longrightarrow \qquad{ {{ \tt{ \frac{3}{2} \: r = -1 }}}}} \\ \\[/tex]
Multiplying both sides by [tex] \sf \dfrac{1}{3}[/tex] we get :
[tex] \\ { \longrightarrow \qquad{ {{ \tt{ \frac{1}{3} \times \frac{3}{2}r = \frac{1}{3} \times -1 }}}}} \\ \\[/tex]
[tex] { \longrightarrow \qquad{ {{ \tt{ \frac{1}{ \cancel3} \times \frac{ \cancel3}{2}r = - \frac{ 1}{ 3} }}}}} \\ \\[/tex]
[tex] { \longrightarrow \qquad{ {{ \tt{ \frac{1}{2}r = - \frac{1}{3} }}}}} \\ \\[/tex]
Now, Multiplying both sides by 2 we get :
[tex] \\ { \longrightarrow \qquad{ {{ \tt{ 2 \times \frac{1}{2}r = 2 \times - \frac{1}{3} }}}}} \\ \\[/tex]
[tex]{ \longrightarrow \qquad{ {{ \tt{ \cancel2 \times \frac{1}{ \cancel2}r = - \frac{2}{3} }}}}} \\ \\[/tex]
[tex]{ \longrightarrow \qquad{ {{ \tt{ {1}r = - \frac{2}{3} }}}}} \\ \\[/tex]
[tex]{ \longrightarrow \qquad{ \frak {{ \pmb{ r = - \frac{2}{3} }}}}} \\ \\[/tex]
