Answer:
[tex] \sf \fbox{Option D have pair of triangles are similiar}[/tex]
Step-by-step explanation:
To prove triangles are pair we will use AAA property.
ln option A the given triangles 1 & 2 have a 36° Angle, but the remaining two angles of both the traingle are not mentioned, as long as we don't know the measure of other two angle of both the traingle we can't say that pair of triangles are similar.
Similarly In option B triangles 3 & 4 can't be pair of similar triangle
In option C triangle 5 & 6 don't have any common angle, hence it does not follows AAA property and the given pair of traingles are not similar.
In option D Two angles of each triangle are given so we can easily find the third angle of both the triangle. let's solve for the third angles of triangle 7 and 8.
in triangle 7,
All three angles of triangle 7 are 30, 60 & 90
Now in triangle 8,
All three angles of triangle 8 are 30, 60 & 90
Hence, both the triangles have same measure of all three angles we can say that triangle 7 & 8 are similar triangle.
Thanks for joining brainly community!