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Val needs to find the area enclosed by the figure. The figure is made by attaching
semicircles to each side of a 46-m-by-46-m square. Val says the area is 1,206.12
m². Find the area enclosed by the figure. Use 3.14 for 1. What error might Val have
made?

Respuesta :

Answer: See below

Step-by-step explanation:

Radius of the semicircle = 46/2 = 23 m

[tex]\therefore$ Area enclosed by the figure $=4 \times$ Area of semicircles + Area of square \begin{aligned} \\&=4 \times 3.14 \times(23)^{2} \times \frac{1}{2}+(46)^{2} \\&=3322.12+2116 \end{aligned} \\\\\\Area enclosed $=5438.12 \mathrm{~m}^{2}$[/tex]

So, Val might have have subtracted 2116 from 3322.12 instead of adding since 3322.12 - 2116 = 1206.12