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Given int[] array, return a new int[] that contains every other element of array. for example, if array = {0, 1, 2, 3, 4, 5}, return {0, 2, 4}.

Hint: How big does the new array have to be?

Tip: Write down an example array to help find the pattern between the index from the old array and the index in the new array.

Respuesta :

issssse

This is how you do it in python:

Code:

def everyother(array):

   return array[::2]

example_array = [0, 1, 2, 3, 4, 5]

print(everyother(example_array))

Output:

[0, 2, 4]

Explenation:

The key to this problem is "array[::2]".

Array[start : stop : step]

Writing "array[::2]" is the same as writing:

Array[0 : -1 : 2] or Begin at 0, stop at the end and take every 2:nd value

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