You are forming words in which the first letter is either P, B, or M; the second letter is either A or E; and the third letter is either N or T. If each possible word is written on a slip of paper and you choose one slip at random, what is the probability that the second letter is an A?

Respuesta :

Using it's concept, it is found that there is a 0.5 = 50% probability that the second letter is an A.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we consider that:

  • For the first letter, there are 3 outcomes.
  • For the second letter, there are 2 outcomes
  • For the third letter, there are 2 outcomes.

Hence, the total number of words is:

T = 3 x 2 x 2 = 12.

With the second letter being A, the number of words is:

D = 3 x 1 x 2 = 6.

Hence, the probability is given by:

p = 6/12 = 0.5.

More can be learned about probabilities at https://brainly.com/question/14398287