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A basketball player shoots a free throw, where the position of the ball is modeled by x = (24cos 48°)t and y = 6.1 + (24sin 48°)t − 16t 2. What is the height of the ball, in feet, when it is 13 feet from the free throw line? Round to three decimal places.
I know how to do this but I keep getting a negative answer, is there an error with the question or am I just doing it wrong

Respuesta :

Maybe ur just not seeing the negative comment on this and tell me which way u are solving it and then i can help.

The height of the ball is 10.053 approx. when it is 13 feet from the free throw line .

What is free throw?

The physics aspect of shooting a free throw involves distance and deviation. Distance is determined by two factors: launch angle and launch speed. Players have a choice between shooting for a larger target by using more arc or going for a shooter's touch and shooting with their ideal arc for their height.

According to the question

A basketball player shoots a free throw, where the position of the ball is modeled

x = (24cos 48°)t

y =  6.1 + (24sin 48°)t − [tex]16t^{2}[/tex]

now

13 feet from the free throw line

x = 13 feet (horizontal distance)

x = (24cos 48°)t

(24cos 48°)t = 13

t ≈ 0.8059

putting values in y to get the vertical height

y =  6.1 + (24sin 48°)t − [tex]16t^{2}[/tex]

y =  6.1 + (24sin 48°)*0.8059 − [tex]16*( 0.8059)^{2}[/tex]

y ≈ 10.053

Hence, the height of the ball is 10.053 approx.

To know more about Free throw here :

https://brainly.com/question/1503439

# SPJ2

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