Respuesta :
The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
What is the factor of a^2-b^2?
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
[tex]= 121b^4 - 49\\= (11b^2)^2 - 7^2\\= (11b^2 + 7)(11b^2 - 7)[/tex]
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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Answer:
(11b2 + 7)(11b2 − 7)
Step-by-step explanation:
just did the test
