The value of the other solution for f(x)=0 is -7. This is obtained by taking the general form of the quadratic equation f(x)=y.
Quadratic function:
- A function is represented by an equation f(x)=ax²+bx+c where a≠0 and b, c are any real numbers.
- This can be generalized into f(x)=y where x is an independent variable and y is a dependent variable.
Given data:
In the table, x values range from -8 to 1
So, we can write using the general form f(x)=y for these values
For x=-8, f(-8)=-2.75
x=-7, f(-7)=0
x=-6, f(-6)=2.25
x=-5, f(-5)=4
x=-4, f(-4)=5.25
x=-3, f(-3)=6
x=-2, f(-2)=6.25
x=-1, f(-1)=6
x=0, f(0)=5.25
x=1, f(1)=4
And 3 is one of the solution to f(x)=0.
Calculating solution for f(x)=0:
It is given that f(x)=0 when x=3
Thus,
f(3)=0
From the table,
f(-7)=0
So, the other solution for the function f(x)=0 is -7.
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