Respuesta :

I think the lateral area is based on the surface area of each prism that make up for it

[tex]\stackrel{\textit{\Large Lateral Area}}{\stackrel{\textit{area of the 6 sides}}{6(12)(15)}\implies 1080} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ p=\stackrel{6\times 12}{72}\\ a=10.39 \end{cases}\implies A=\cfrac{1}{2}(10.39)(72)\implies 374.04 \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{\Large Areas}}{\stackrel{lateral}{1080}~~ + ~~\stackrel{two~hexagons}{2(374.04)}}\implies 1828.08\qquad \leftarrow \textit{total surface area}[/tex]