The equation of the line of the other leg of the right triangle if it shares the vertice of (10,0) is y = -1/3x + 10/3
How to find the equation of a line?
The equation of a line in slope-intercept form is expressed as y = mx + b
where
m is the slope
b is the y-intercept
Given the coordinate points (-2, 4) and (10, 0)
Find the slope
Slope = -4/12
Slope = -1/3
Determine the y-intecept
0 = -1/3(10) + b
b = 10/3
Determine the equation
y = -1/3x + 10/3
Hence the equation of the line of the other leg of the right triangle if it shares the vertice of (10,0) is y = -1/3x + 10/3
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