Respuesta :

TheAmethyst

Answer:

  • Solution of equation ( q ) = 16

Step-by-step explanation:

In this question we have given an equation that is 3 ( q - 7 ) = 27 and we have asked to solve this equation that means to find the value of q .

Solution : -

[tex] \quad \: \longmapsto \: 3(q - 7) = 27[/tex]

Step 1 : Solving parenthesis :

[tex]\quad \: \longmapsto \:3q - 21 = 27[/tex]

Step 2 : Adding 21 on both sides :

[tex]\quad \: \longmapsto \:3q - \cancel{ 21} + \cancel{21} = 27 + 21[/tex]

On further calculations we get :

[tex]\quad \: \longmapsto \:3q = 48[/tex]

Step 3 : Dividing by 3 from both sides :

[tex]\quad \: \longmapsto \: \frac{ \cancel{3}q}{ \cancel{3}} = \cancel {\frac{48}{3} }[/tex]

On further calculations we get :

[tex]\quad \: \longmapsto \: \pink{\boxed{\frak{q = 16}}}[/tex]

  • Therefore, solution of equation ( q ) is 16 .

Verifying : -

Now we are very our answer by substituting value of q in the given equation . So ,

  • 3 ( q - 7 ) = 27

  • 3 ( 16 - 7 ) = 27

  • 3 ( 9 ) = 27

  • 27 = 27

  • L.H.S = R.H.S

  • Hence, Verified.

Therefore, our solution is correct .

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Chandasmita

Answer:

  • The value of q is 16

[tex] \: [/tex]

Step-by-step explanation:

So here, a equation is given and we are asked to solve the equation.

[tex] \\ \dashrightarrow \sf \qquad3(q-7)=27 \\ \\ [/tex]

For this, we have to use the Distributive property, which is :

  • a(b + c) = ab + ac

[tex]\\ \dashrightarrow \sf \qquad3q-21=27 \\ \\ [/tex]

Transposing the constant term (-21) to the right side we get :

[tex]\\ \dashrightarrow \sf \qquad3q=27 + 21 \\ \\ [/tex]

Adding the like terms :

[tex] \\ \dashrightarrow \sf \qquad3q=48 \\ \\ [/tex]

Now, We'll divide both sides by 3 :

[tex] \\ \dashrightarrow \sf \qquad \frac{3q}{3} = \frac{48}{3} \\ \\ [/tex]

[tex]\dashrightarrow \bf \qquad \: q=16 \\ \\ [/tex]