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A rifle of mass 2 kg is suspended by strings. the rifle fires a bullet of mass 0.01 kg at a speed of 200 m/s. the recoil velocity of the rifle is about

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col7kings

Answer:

-1m/s

Explanation:

P gun+ P bullet= P gun + P bullet

u= for both at first is zero

then

-P gun=P bullet

hence

P=mv

-2v=(0.01×200)

-2v=2

v= -1m/s

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