What is the molality of a solution made by dissolving 6 moles of NaOH in 3 kg
of water?
O A. 2 mol/kg
OB. 0.5 mol/kg
B.
C. 3 mol/kg
O D. 0.33 mol/kg

(AP3X) A- 2 mol/kg

Respuesta :

given:

Moles of solute NaOH = 6 mol

Mass of solvent water = 3 kg

to find:

the molarity

solution:

[tex]molarity = \frac{moles \: of \: solute}{mass \: of \: solvent} [/tex]

[tex]m = \frac{6mol}{3kg} [/tex]

[tex] = 2mol |kg[/tex]

therefore, the molality of a solution made by dissolving 6 moles of NaOH in 3 kg of water is 2mol/kg.