Moles of solute NaOH = 6 mol
Mass of solvent water = 3 kg
the molarity
[tex]molarity = \frac{moles \: of \: solute}{mass \: of \: solvent} [/tex]
[tex]m = \frac{6mol}{3kg} [/tex]
[tex] = 2mol |kg[/tex]
therefore, the molality of a solution made by dissolving 6 moles of NaOH in 3 kg of water is 2mol/kg.