Respuesta :
The volleyball is 14 feet above the ground at the instant the player begins her jump.
What is the equation of motion?
It is defined as the equation by which we can find the motion of a physical particle with respect to time. It is the representation of physical entity movement in a mathematical function.
We have two equation for two different situations:
[tex]\rm h(t) = 14 - 16t^2\\[/tex] (falling volleyball as a function of time t)
[tex]\rm h(t) = 7+24t-16t^2[/tex] (the hands of a player jumping up to spike the
ball as a function of time t)
First, we have to find the height of the ball above the ground at the instants the player begins to jump:
At t = 0 when the player begins to jump
Put t = 0 in the second equation, we get:
[tex]\rm h(0) = 7+24\times 0-16\times0^2[/tex]
Height of the hand, h = 7 units
Now put t = 0 in the first equation, we get;
[tex]\rm h(0) = 14 - 16\times0^2[/tex]
h = 14 units.
Thus, the volleyball is 14 feet above the ground at the instant the player begins her jump.
Learn more about the equation of the motion here:
brainly.com/question/13514745
Answer:
the answer is B on E 2020
Step-by-step explanation:
cuz i said so :|
